cd3b40c9c7
Support of the new version 1 subscription API as well as the previous version 1 API. Test Plan: Tested with ptpdemo app. Pass: Subscribe ptp notification using old API Pass: Subscribe ptp notification using new API Pass: List all subscriptions (both old and new versions) Pass: Get a subscription by ID (both old and new versions) Pass: Delete subscription by ID Story: 2010056 Task: 45688 Change-Id: I153ec23b2abb712d30279aa9e1c84e038a69a24c Signed-off-by: Teresa Ho <teresa.ho@windriver.com>
66 lines
2.1 KiB
Python
66 lines
2.1 KiB
Python
#coding=utf-8
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#
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# Copyright (c) 2021 Wind River Systems, Inc.
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#
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# SPDX-License-Identifier: Apache-2.0
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#
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import os
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import json
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import re
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import requests
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import logging
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from notificationclientsdk.common.helpers.nodeinfo_helper import NodeInfoHelper
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LOG = logging.getLogger(__name__)
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from notificationclientsdk.common.helpers import log_helper
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log_helper.config_logger(LOG)
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def notify(subscriptioninfo, notification, timeout=2, retry=3):
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result = False
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while True:
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retry = retry - 1
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try:
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headers = {'Content-Type': 'application/json'}
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data = json.dumps(notification)
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url = subscriptioninfo.EndpointUri
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response = requests.post(url, data=data, headers=headers, timeout=timeout)
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response.raise_for_status()
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result = True
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return response
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except requests.exceptions.ConnectionError as errc:
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if retry > 0:
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LOG.warning("Retry notifying due to: {0}".format(str(errc)))
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continue
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raise errc
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except requests.exceptions.Timeout as errt:
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if retry > 0:
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LOG.warning("Retry notifying due to: {0}".format(str(errt)))
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continue
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raise errt
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except requests.exceptions.RequestException as ex:
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LOG.warning("Failed to notify due to: {0}".format(str(ex)))
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raise ex
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except requests.exceptions.HTTPError as ex:
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LOG.warning("Failed to notify due to: {0}".format(str(ex)))
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raise ex
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except Exception as ex:
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LOG.warning("Failed to notify due to: {0}".format(str(ex)))
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raise ex
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return result
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def parse_resource_address(resource_address):
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# The format of resource address is:
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# /{clusterName}/{siteName}(/optional/hierarchy/..)/{nodeName}/{resource}
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# Assume no optional hierarchy for now
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clusterName = resource_address.split('/')[1]
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nodeName = resource_address.split('/')[2]
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resource_path = re.split('[/]', resource_address, 3)[3]
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return clusterName, nodeName, resource_path
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