Prepare one zuul docker job for all services

We want to have one flow for building Docker images of all Monasca
components. Every component should have `docker` folder and in this
folder file with name `build_image.sh` should be placed. By having one
global Zuul we could force this convention. Also this is good for
avoiding code duplication. Remove timeouts. They was unnecessary big.

Story: 2001694
Task: 28994
Change-Id: Iee7de1d8e873817a3b6f72e7ecc815bd8d6eb705

.zuul.yaml

@@ -37,9 +37,18 @@
 
 - job:
     name: docker-build-monasca-base
-    timeout: 10200
-    post-timeout: 3600
-    run: playbooks/run.yml
+    run: playbooks/docker_build_base.yml
+    required-projects:
+      - openstack/monasca-common
+    attempts: 1
+    irrelevant-files:
+      - ^.*\.rst$
+      - ^.*\.md$
+      - ^doc/.*$
+
+- job:
+    name: docker-build-monasca-service
+    run: playbooks/docker_build_service.yml
     required-projects:
       - openstack/monasca-common
     attempts: 1

playbooks/docker_build_service.yml

@@ -0,0 +1,19 @@
+---
+- hosts: all
+  tasks:
+    - name: Run node setup script
+      shell: "{{ zuul.projects['git.openstack.org/openstack/monasca-common'].src_dir }}/playbooks/setup_ci.sh"
+      become: true
+
+    - name: Changing permission of Docker socket to 666
+      file:
+        path: /run/docker.sock
+        mode: 666
+      become: true
+
+    - name: Build Docker image
+      shell: "{{ zuul.project.src_dir }}/docker/build_image.sh {{ zuul.tag if zuul.pipeline == 'release' else zuul.branch | basename }}"
+      become: true
+
+    - name: List images
+      shell: "docker images --format '{% raw %}{{ .Repository }}:{{ .Tag }}{% endraw %}' | grep monasca"